Решите пожалуйста 1,2 номер

▪1. a)
$\frac{3b - 2}{1 - 2b} = \frac{3 \times 1 \frac{1}{6} - 2}{1 - 2 \times ( - 1 \frac{1}{6}) } = \frac{3 \times \frac{7}{6} - 2}{1 - 2 \times (- \frac{ {7} }{6} )} = \frac{ \frac{7}{2} - 2}{1 + \frac{7}{3} } = \frac{3 \frac{1}{2} - 2}{1 + 2 \frac{1}{3} } = \frac{1 \frac{1}{2} }{ 3 \frac{1}{3} } = \frac{ \frac{3}{2} }{ \frac{10}{3} } = \frac{9}{20} = 0.45$
▪1. б)
$4x + 3y = 4 \times 1.2 + 3 \times ( - 2.1) = \frac{4 \times 12}{10} - \frac{3 \times 21}{10} = \frac{48 - 63}{10} = - \frac{15}{10} = - 1.5$

▪2. а)

$\frac{2 - 3b}{6b - 3} = \frac{2 - 3 \times 0.6}{6 \times ( - 0.6) - 3} = \frac{2 - 1.8}{ - 3.6 - 3} = \frac{0.2}{ - 6.6} = - \frac{ \frac{2}{10} }{ \frac{66}{10} } = - \frac{2 \times 10}{10 \times 66} = - \frac{1}{33}$

▪2. б)

$3x + 4y = 3 \times 2 \frac{5}{6} + 4 \times ( - 2 \frac{3}{8} ) = 6 \frac{3 \times 5}{6} - 8 \frac{4 \times 3}{8} = 6 \frac{ {5} }{2} - 8 \frac{3}{2} = 8 \frac{1}{2} - 9 \frac{1}{2} = - 1$