Помогите пожалуйста с 5 заданием

Решите задачу:

${(a + b)}^{3} = (3x + 1 + x - 2) ^{3} = (4x - 1)^{3} = 64 {x}^{3} - 3 \times 16 {x}^{2} \times 1 + 3 \times 4x \times {1}^{2} - 1 = 64 {x}^{3} - 48 {x}^{2} + 12x - 1$
${(a - b)}^{3} = (3x + 1 - x + 2) ^{3} = (2x + 3)^{3} = 8 {x}^{3} + 3 \times 4 {x}^{2} \times 3 + 3 \times 2x \times 9 + 27 = 8 {x}^{3} + 36{x}^{2} + 54x + 27$

${(a + b)}^{2} = (3x + 1 + x - 2)^{2} = (4x - 1) ^{2} = 16 {x}^{2} - 8x + 1$

${(a - b)}^{2} = {(3x + 1 - x + 2)}^{2} = {(2x + 3)}^{2} = 4 {x}^{2} + 12x + 9$