0 \\ f(-\frac{2}{5}k)=\dfrac{k}{|-\frac{2}{5}k|} = \dfrac{1}{\frac{2}{5}} =\frac{5}{2} =2,5\\ f(-5k)=\dfrac{k}{|-5k|} = \dfrac{1}{5} =0,2\\ f(-\frac{2}{5}k)+ f(-5k)=2,5+0,2=2,7 " alt=" f(x)=\frac{k}{|x|},\ k>0 \\ f(-\frac{2}{5}k)=\dfrac{k}{|-\frac{2}{5}k|} = \dfrac{1}{\frac{2}{5}} =\frac{5}{2} =2,5\\ f(-5k)=\dfrac{k}{|-5k|} = \dfrac{1}{5} =0,2\\ f(-\frac{2}{5}k)+ f(-5k)=2,5+0,2=2,7 " align="absmiddle" class="latex-formula">
Ответ: 2,7
