Решите с объяснением!А7 и В1

A7)
$\frac{16 {x}^{17} \times {(2x)}^{ - 3} }{ {( {x}^{ - 3}) }^{ - 4} } = \frac{ 16{x}^{17} \times {2}^{ -3 } \times {x}^{ - 3} }{ {x}^{ - 3 \times ( - 4)} } = \frac{16 {x}^{17 - 3} \times \frac{1}{8} }{ {x}^{12} } = \frac{2 {x}^{14} }{ {x}^{12} } = 2 {x}^{14 - 12} = 2 {x}^{2}$
при х = 1,5:
$2 \times {(1.5)}^{2} = 2 \times {( \frac{3}{2}) }^{2} = 2 \times \frac{9}{4} = \frac{9}{2} = 4.5$
Б1)
$\frac{ {9}^{ - 6} \times {3}^{5} }{ {27}^{ - 3} } = \frac{ {3}^{2 \times ( - 6)} \times {3}^{5} }{ {3}^{3 \times ( - 3)} } = \frac{ {3}^{ - 12} \times {3}^{5} }{ {3}^{ - 9} } = \frac{ {3}^{ - 12 + 5} }{ {3}^{ - 9} } = \frac{ {3}^{ - 7} }{ {3}^{ - 9} } = {3}^{ - 7 - ( - 9)} = {3}^{ - 7 + 9} = {3}^{2} = 9$
Ответ: 2)