Log 17(x 2+x-7)=log 17(-x+1)

Question

Log 17(x 2+x-7)=log 17(-x+1)

Answer 1

0} \atop {x^2+x-7=-x+1}} \right. \Leftrightarrow \left \{ {{x<1} \atop {x^2+2x-8=0}} \right. \Leftrightarrow \left \{ {{x<1} \atop {x_{1,2}=-4; \ 2}} \right. \Leftrightarrow x=-4 \\ \\ OTBET: -4 " alt=" log _{17}(x^2+x-7)=log_{ 17}(-x+1)\\ \\ \left \{ {{-x+1>0} \atop {x^2+x-7=-x+1}} \right. \Leftrightarrow \left \{ {{x<1} \atop {x^2+2x-8=0}} \right. \Leftrightarrow \left \{ {{x<1} \atop {x_{1,2}=-4; \ 2}} \right. \Leftrightarrow x=-4 \\ \\ OTBET: -4 " align="absmiddle" class="latex-formula">