Помогите решить эту задачу
(2aˇ4 - 3bˇ3)/(1-aˇ2) , a=-1/2, b=-1/3
aˇ4=(-1/2)ˇ4=+1/16 , bˇ3=(-1/3)ˇ3=-1/27 , aˇ2= (-1/2)ˇ2=+1/4
(2/16+3/27)/(1-1/4)=(1/8+1/9)/(3/4)=(17/72)/(3/4)=(17/72)(4/3)=17/18)(1/3)=17/54
(2a⁴ - 3b³)/(1 - a²) при a = -1/2 и b = -1/3
(2· 1/16 - 3 · (- 1/27))/(1 - 1/4) = (1/8 + 1/9) : 3/4 = (9/72 + 8/72) : 3/4 =
= 17/72 : 3/4 = 17/54