2 \\ \\ \frac{4x-1}{x-3}-2>0\\ \\ \frac{4x-1-2(x-3)}{x-3}>0 \\ \\ \frac{4x-1-2x+6}{x-3}>0 \\ \\ \frac{2x+5}{x-3}>0 \\ \\ 1) \ 2x+5=0 \\ 2x=-5 \\ x=\frac{-5}{2}=-2.5 \\ \\ 2) \ x-3 \neq 0 \\ x \neq 3 \\ \\ ++++(-2.5)----(3)++++>x \\ \\ OTBET: \ x \in (-\infty; -2.5) \ \cup \ (3; +\infty) " alt=" \frac{4x-1}{x-3}>2 \\ \\ \frac{4x-1}{x-3}-2>0\\ \\ \frac{4x-1-2(x-3)}{x-3}>0 \\ \\ \frac{4x-1-2x+6}{x-3}>0 \\ \\ \frac{2x+5}{x-3}>0 \\ \\ 1) \ 2x+5=0 \\ 2x=-5 \\ x=\frac{-5}{2}=-2.5 \\ \\ 2) \ x-3 \neq 0 \\ x \neq 3 \\ \\ ++++(-2.5)----(3)++++>x \\ \\ OTBET: \ x \in (-\infty; -2.5) \ \cup \ (3; +\infty) " align="absmiddle" class="latex-formula">