x " alt=" \frac{7}{x^2-5x+6} +\frac{9}{x-3} +1\leq 0\\x^2-5x+6=(x-3)(x-2)\\\left \{ {{x_1x_2=6} \atop {x_1+x_2=5}} \right. [{ {{x=3} \atop {x=2}} \right. \\ \frac{7}{x^2-5x+6} +\frac{9}{x-3} +1\leq 0 |*(x-3)(x-2)\\7+9x-18+x^2-5x+6\leq 0\\x^2+4x-12\leq 0\\x^2+4x-12=0\\\left \{ {{x_1x_2=-12} \atop {x_1+x_2=-4}} \right. [{ {{x=2} \atop {x=-6}} \right. \\(x+6)(x-2)\leq 0\\---[-6]+++[2]--->x " align="absmiddle" class="latex-formula">
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