Решите систему уравнений способом алгебраического сложения

$\left \{ {{\frac{v+1}{2u-4}=\frac{1}{2}} \atop {\frac{5u+v}{3u+6}=1}} \right.$

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ОДЗ:

$\left \{ {{2u-4\neq0} \atop {3u+6\neq0}} \right. \\ \\ \left \{ {{2u\neq4} \atop {3u\neq-6}} \right. \\ \\ \left \{ {{u\neq2} \atop {u\neq-2}} \right.$

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$\left \{ {{2u-4=2(v+1)} \atop {5u+v=3u+6}} \right. \\ \\ \left \{ {{2u-4=2v+2} \atop {5u+v-3u=6}} \right. \\ \\ \left \{ {{2u-2v=6} \atop {2u+v=6}} \right. \\ \\ \left \{ {{u-v=3} \atop {2u+v=6}} \right. \\ \\ \left \{ {{u-v+2u+v=3+6} \atop {u-v=3}} \right. \\ \\ \left \{ {{3u=9} \atop {u-v=3}} \right. \\ \\ \left \{ {{u=3} \atop {3-v=3}} \right. \\ \\ \left \{ {{u=3} \atop {v=0}} \right.$