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Решите задачу:

$73,13-(1\frac{1}{2}x+\frac{13}{20})\cdot(-2) =-4,5x\\ \\ 73,13-(\frac{3}{2}x+\frac{13}{20})\cdot(-2) =-4,5x \\ \\ 73,13+3x+\frac{13}{10}=-4,5x \\ \\ 73,13+3x+1,3=-4,5x \\ 74,43+3x=-4,5x\\ 3x+4,5x=-74,43 \\ 7,5x=-74,43\\ x=-74,43:7,5\\ x=-744,3:75\\ x=-9,924$

$-3\frac{7}{9}x+19\frac{4}{15} -11\frac{1}{3}x=-7\cdot(3\frac{1}{21}x-\frac{1}{7}) \\ \\ -3\frac{7}{9}x+19\frac{4}{15} -11\frac{3}{9}x=-7\cdot(\frac{64}{21}x-\frac{1}{7}) \\ \\ -14\frac{10}{9}x+19\frac{4}{15} =-\frac{64}{3}x+1 \\ \\ -15\frac{1}{9}x+19\frac{4}{15} =-21\frac{1}{3}x+1 \\ \\ -15\frac{1}{9}x+21\frac{1}{3}x=1-19\frac{4}{15} \\ \\ -15\frac{1}{9}x+21\frac{3}{9}x=-18\frac{4}{15} \\ \\ 6\frac{2}{9}x=-18\frac{4}{15} \\ \\ x=-18\frac{4}{15}: 6\frac{2}{9}$

$x=-\frac{274}{15}: \frac{56}{9}\\\\ x=-\frac{274}{15}\cdot\frac{9}{56}\\\\ x=-\frac{411}{140}\\\\ x=-2\frac{131}{140}$