1) 3 |x| - 1 = 02) 2 |x| + 3 = 03) |3x + 2| - 4 = 04) |2x - 1| + 7 = 8

Решите задачу:

$1)3 |x| - 1 = 0 \\ |x| = \frac{1}{3} \\ x1 = \frac{1}{3} \\ x2 = - \frac{1}{3}$
$2)2 |x| + 3 = 0 \\ |x| = - \frac{3}{2} \\ x = - \frac{3}{2} \\ x = \frac{3}{2}$
$3) |3x + 2| - 4 = 0 \\ |3x + 2| = 4 \\ 1)3x + 2 = 4 \\ x = \frac{2}{3} \\ 2) |3x + 2| = - 4 \\ x = - 2$
$4) |2x - 1| + 7 = 8 \\ |2x - 1| = 1 \\ 1)2x - 1 = 1 \\ x = 1 \\ 2)2x - 1 = - 1 \\ x = 0$