Решите квадратное уравнение: 1.3x^2=18x 2.x^2-16x+63=0
1) 3x² = 18x 3x² - 18x = 0 3x(x - 6) = 0 x₁ = 0; x₂ = 6 2) x² - 16x + 63 = 0 D/4 = (-16/2)² - 63 = 64 - 63 = 1 x₁ = -(-16/2) + 1 = 8 + 1 = 9 x₂ = -(-16/2) - 1 = 8 - 1 = 7
3x²=18x x²=6x x²-6x=0 x(x-6)=0 x=0 x-6=0 x=0 x=6 x1=0; x2=6 __________ x²-16x+63=0 x²-7x-9x+63=0 x(x-7)-9(x-7)=0 (x-7)*(x-9)=0 x-7=0 x-9=0 x=7 x=9 x1=7; x2=9