Y=g(x) найдите значению функций в заданных точках g(x)=6/x+1+3, x=-5;0;1/5...

Решите задачу:

$g(x) = \frac{6}{x + 1} + 3 \\ g( - 5) = \frac{6}{ - 5 + 1} + 3 = \frac{6}{ - 4} + 3 = - \frac{ 3}{2} + 3 = \frac{3}{2} \\ g(0) = \frac{6}{0 + 1} + 3 = 6 + 3 = 9 \\ g( \frac{1}{5} ) = \frac{6}{ \frac{1}{5} + 1} + 3 = \frac{6}{ \frac{6}{5} } + 3 = 5 + 3 = 8$
$g(x) = \frac{1}{x - 4} \\ g( - 1) = \frac{1}{ - 1 - 4} = - \frac{1}{5} \\ g(1) = \frac{1}{1 - 4} = - \frac{1}{3} \\ g(4.5) = \frac{1}{4.5 - 4 } = \frac{1}{0.5} = 2$