Розвязати...................

Question

Розвязати...................

---

Answer 1

(x-3)*√(x²+x-2)≥0
x²+x-2≥0
D=1+8=9=3²
x=(-1±3)/2
x1=-2;x2=1
x€(-oo;-2]U[1;+oo) ODZ
√(x²+x-2)≥0
x-3≥0;x≥3

{x€(-oo;-2]U[1;+oo)
{x≥3 ;
=>x€[3;+oo)U{-2;1}