Решите систему x-3y=1 x*y=14

Решите задачу:

$\left \{ {{x-3y= 1} \atop {x*y=14}} \right. \left \{ {{x=1+3y} \atop {x*y=14}} \right. (1+3y)y=14; y1=2; y2=\frac{-7}{3}; x1=7; x2=-6; (x1,y1)=(7,2) (x2,y2)= (-6, \frac{-7}{3} \left \{ {{7-3*2=1} \atop {7*2=14}} \right. \left \{ {-6-3*(\frac{-7}{3} } \atop {-6*(\frac{-7}{3} }} \right. \left \{ {{1=1} \atop {14=14}} \right. \left \{ {{1=1} \atop {14=14}} \right. (x1,y1)=(7,2) (x2,y2)=(-6, \frac{-7}{3}$