task/29489913 * * * i =√(-1) ; i² = -1 * * *
z₁ +z₂ =(1+i) +(2-i) =3 ;
z₁ -z₂ =(1+i) - (2-i) = -1 +2 ;
z₁ *z₂ =(1+i) (2-i) = 2-i +2i - i²= 2+ i - i² = 2+ i - (-1) = 3 + i;
z₁ : z₂ = (1+i) / (2-i )= (1+i ) * (2+i)/ (2-i )(2+i) =( 2+i +2i + i²) /(4 -i²) =(1+3i) /5 =
1/5 +(3/5)i = 0,2 +0 ,6 i .