Пж помогите решит 1)-3•(2x-7)=16-2(-2x+1) 2) 13•2(-4x+1)=18 3) -4x+6=20-4(3x+5)

Question

Пж помогите решит 1)-3•(2x-7)=16-2(-2x+1) 2) 13•2(-4x+1)=18 3) -4x+6=20-4(3x+5)

Answer 1

1)

-3•(2x-7)=16-2(-2x+1)

-6x  + 21 = 16 + 4x - 2

-6x + 21 = 14 + 4x

4x + 6x = 21 - 14

10x = 7

x = 7 : 10

x = 0,7

2)

13•2(-4x+1)=18

3 * (-8x + 2 ) = 18

-24x + 6 = 18

-24x = 18 - 6

-24x = 12

x = -12 : 24

x = -0,5

3)

-4x+6=20-4(3x+5)

-4x + 6 = 20 - 12x - 20

-4x + 6 = -12

12x - 4x = -6

8x = -6

x = -6 : 8

x = -0,75