Помогите решить. {6(x-3)=7y-1; 2(y+6)=3x+2;

Решите задачу:

$\displaystyle\left \{ {{6(x-3)=7y-1} \atop {2(y+6)=3x+2}} \right. ~~~\Leftrightarrow~~~\left \{ {{6x-18=7y-1} \atop {2y+12=3x+2}} \right.~~~\Leftrightarrow\\ \\ \\ \displaystyle\left \{ {{6x-18=7y-1} \atop {-3x+10=-2y~~~|\times2}} \right. ~~\Leftrightarrow~~\left \{ {{6x-17=7y} \atop {-6x+20=-4y}} \right. ~~+~~\Leftrightarrow\\ \\ \\\displaystyle\left \{ {{3=3y} \atop {6x-20=4y}} \right. ~~~\Leftrightarrow~~~\left \{ {{y=1} \atop {6x=20+4\cdot 1}} \right. ~~~\Leftrightarrow$

$\displaystyle\boldsymbol{\left \{ {{y=1} \atop {x=4}} \right.}$