(3+4i)(3-4) , (5+3i)(2-5),(-2-1)(1+i),4+2i+(-1+61)(6-1),(3-2i)(5+4i)-7i+1 решите пжт

Question

(3+4i)(3-4) , (5+3i)(2-5),(-2-1)(1+i),4+2i+(-1+61)(6-1),(3-2i)(5+4i)-7i+1 решите пжт

Answer 1

3+4i)(3-4i)=9+12i-12i+16=25  

(5+3i)(2-5i)= 10+6i-25i+15=25-19i  

(-2-i)(1+i)= -2-i-2i+1=-(1+3i)  

4+2i+(-1+6)(6-i))= 4+2i-6+36+i-6i=32-3i  

(3-2I)(5i+4i)-7i+1= 15i-105i+12i-84i-7i+1=1-169i  

(2/3 - 1/3i)(1/3+4/3i)= 7i/9+2/3  

(0,2-0,3i)(0,5+0,4i)=0,13-0,07i