(3x+2)(4x-1)-12=x решите срочно пж
(3x+2)(4x-1)-12=x
12x²-3x+8x-2-12-x=0
12x²+4x-14=0
6x²+2x-7=0
D= 4+168=172
x1= (-2+2√43)/12= (-1+√43)/6
x2= (-2-2√43)/12= (-1-√43)/6