Помогите a) b) c) d).

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Помогите a) b) c) d).image

Математика (124 баллов) | 47 просмотров
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а)1ц 1/5 * 1ц 2/3 * 1/7 + (1ц 1/7) ² = 6/5 * 5/3 * 1/7 + (8/7) ² = 2/7 + 64/49 = 14 / 49 + 64/49 =78\49= 1 ц 29/49

б)(2ц 1/6 - 2/3) ² - 2ц 1/5 = ( 13/6 - 4/6) ² -11/5 = (3/2) ² - 11/5 =9/4 - 11/5 =45/20-44/20=1/20

с)10 - 2 * (3ц 1/5 - 2ц 1/4 * 1/3) = 10 - 2 * (16/5 - 9/4 * 1/3) = 10 - 2 * (16/5 - 3 / 4) =

= 10 - 32/5+6/4 =200/20 - 128/20+30\20 =102/20=51/10= 5,1

д)(7/3 - 5/12 + 1ц 1/2): (2ц 3/4 - 5/6) = (7\3 - 5/12 + 3/2): (11\4 - 5/6) =(28\12-5\12+18/12) :(33/12-10/12)=41/12*12/23=41/23 = 1ц 18/23



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Решите задачу:

a) \\ \frac{6}{5} \times \frac{5}{3} \times \frac{1}{7} + ( \frac{8}{7} ) {}^{2} = 2 \times \frac{1}{7} + \frac{64}{49} = \frac{2}{7} + \frac{64}{49} = \frac{78}{49} = 1 \frac{29}{49} \\ \\ b)\\( \frac{13}{6} - \frac{2}{3} ) {}^{2} - \frac{11}{5} = ( \frac{3}{2} ) {}^{2} - \frac{11}{5} = \frac{9}{4} - \frac{11}{5} = \frac{1}{20} = 0.05 \\ \\ c) \\ 10 - 2( \frac{16}{5} - \frac{9}{4} \times \frac{1}{3} ) = 10 - 2( \frac{16}{5} - \frac{3}{4} ) = 10 - 2 \times \frac{49}{20} = 10 - \frac{49}{10} = \frac{51}{10} = 5.1 \\ \\ d) \\ ( \frac{7}{3} - \frac{5}{12} + \frac{3}{2} ) \div ( \frac{11}{4} - \frac{5}{6} ) = \frac{41}{12} \div \frac{23}{12} = \frac{41}{12} \times \frac{12}{23} = 41 \times \frac{1}{23} = \frac{41}{23} = 1 \frac{18}{23}
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