Cos(3π/2-2x)=√2 sinx

Question

Cos(3π/2-2x)=√2 sinx

Answer 1

-sin2x=√2sinx
2sinxcosx+√2sinx=0
sinx(2cosx+√2)=0
sinx=0
x=Пn, n∈Z
cosx=-√2/2
x=+-5П/4+2Пk k∈Z