task/29641061
∫( 5x⁴ -1/x²)dx =∫ 5x⁴dx -∫(1/x²)dx =5∫x⁴dx -∫x⁻²dx =5*x⁵/5 + x⁻¹ +C =x⁵ + 1/x+C .
∫(x⁵ -3) /x² dx =∫(x³ - 3/x² ) dx =∫x³dx -3∫x⁻²dx = x⁴/4 +3/x +C.
∫(x³ -cosx) dx = ∫x³dx -∫cosx dx = x⁴/4 - sinx +C.
∫ [(1 +cos²x) / cos²x] dx = ∫( 1/cos²x + 1)dx = ∫( 1/cos²x)dx+ ∫dx =tgx +x +C.