Помогите решить премеры, пожалуйста

Question 1

Question 2

Шестое не видно но вот остальное

Question 3

Прошу побыстрей

Question 4

Решите задачу:

$1 - \frac{2}{7} = \frac{7}{7} - \frac{2}{7} = \frac{5}{7}$

$\frac{3}{5} + \frac{7}{15} = \frac{9}{15} + \frac{7}{15} = \frac{16}{15} = 1 \frac{1}{15}$
$\frac{4}{7} + \frac{1}{21} = \frac{12}{21} + \frac{1}{21} = \frac{13}{21}$
$\frac{5}{6} - \frac{2}{5} = \frac{25}{30} - \frac{12}{30} = \frac{13}{30}$
$1 \frac{1}{2} - \frac{3}{8} = 1 \frac{4}{8} - \frac{3}{8} = 1 \frac{1}{8}$
$2 \frac{1}{2} + 3 \frac{1}{5} = 5 \frac{5 + 2}{10} = 5 \frac{7}{10}$
$\frac{2}{3} \times \frac{6}{7} = \frac{2 \times 2}{1 \times 7} = \frac{4}{7}$
$1 \frac{1}{2} \times 2 \frac{3}{5} = \frac{3}{2} \times \frac{13}{5} = \frac{39}{10} = 3 \frac{9}{10}$
$8 \frac{1}{2} \times 4 = \frac{17 \times 4}{2 \times 1} = \frac{17 \times 2}{1 \times 1} = \frac{34}{1} = 34$
$2 \frac{1}{5} \div \frac{2}{3} = \frac{11}{5} \times \frac{3}{2} = \frac{33}{10} = 3 \frac{3}{10}$
$\frac{6}{7} \div \frac{3}{8} = \frac{6}{7} \times \frac{8}{3} = \frac{2 \times8 }{ 7\times 1} = \frac{16}{7} = 2\frac{2}{7}$
$17 \frac{1}{2} \div 2 = \frac{35}{2} \div \frac{2}{1} = \frac{35}{2} \times \frac{1}{2} = \frac{35}{4} = 8 \frac{3}{4}$
$4 \frac{1}{2} \div 2 \frac{1}{5} = \frac{9}{2} \div \frac{11}{5} = \frac{9}{2} \times \frac{5}{11} = \frac{45}{22} = 2 \frac{1}{22}$
$6 \div 2 \frac{1}{5} = \frac{6}{1} \div \frac{11}{5} = \frac{6}{1} \times \frac{5}{11} = \frac{30}{ 11 } = 2 \frac{8}{11}$
$\frac{2}{3} \times \frac{6}{7} \div \frac{1}{2} = \frac{2 \times 2}{1 \times 7} \times \frac{2}{1} = \frac{4 \times 2}{7 \times 1} = \frac{8}{7} = 1\frac{1}{7}$