- 3} \frac{ {x}^{2} + 5x + 6}{ {x}^{2} + 6x + 9 } = \{ \frac{0}{0} \} = \lim \limits _{x - > - 3} \frac{(x + 3)(x + 2)}{(x + 3 {)}^{2} } = \lim \limits _{x - > - 3} \frac{x + 2}{x + 3 } = \frac{ - 1}{0} = \infty " alt=" \lim \limits _{x - > - 3} \frac{ {x}^{2} + 5x + 6}{ {x}^{2} + 6x + 9 } = \{ \frac{0}{0} \} = \lim \limits _{x - > - 3} \frac{(x + 3)(x + 2)}{(x + 3 {)}^{2} } = \lim \limits _{x - > - 3} \frac{x + 2}{x + 3 } = \frac{ - 1}{0} = \infty " align="absmiddle" class="latex-formula">