task/29656371
1 . A = { -3 ; 2 }
x²+x -6 =0 ⇔ x²+3x -2x -6 =0⇔x(x+3) -2(x+3) =0⇔(x+3)(x-2) =0 ⇔ [ x = -3 ; x=2.
2. B = [ -2; 0) ∪ [ 3 ; ∞) .
(x+2)(3 -x) / x ≤ 0 ⇔ (x+2)(x -3 ) / x ≥ 0 ⇒ x ∈ [ -2; 0) ∪ [ 3 ; ∞)
" - " " + " " - " " + "
------------ [ -2] --------------- (0) ---------------- [3]----------------
3. A \ B = { -8 ; -3; 4 ; 6 ; 9 } B \C = { 0 ; 2 ;3 } ( A∪ B) ∩C ={- 3; 1 ; 4 ; 6}
( A ∩C ) ∪ B = {- 3; 0 ; 1 ; 2 ;3 ; 4 ; 6}