Помогити пожалуйста даю 50 балов 6,6

Решите задачу:

$3 \times 12 ^{ - 2} = \frac{3}{ {12}^{2} } = \frac{3}{144}$
${2}^{ - 3} + {6}^{ - 1} = \frac{1}{8} + \frac{1}{6} = \frac{7}{24}$
${3}^{ - 2} - ( - 3) ^{ - 1} = \frac{1}{9} + \frac{1}{3} = \frac{4}{9}$
$- 2 \times {4}^{ - 3} = - \frac{2}{64} = - \frac{1}{32}$
$3 \times {4}^{ - 2} + {2}^{ - 3} = \frac{3}{16} + \frac{1}{8} = \frac{5}{16}$
${0.4}^{0} - ( - 0.25) ^{ - 3} = 1 + {4}^{3} = 65$
$( - 2.5) ^{ - 2} + ( - \frac{2}{5} )^{ - 2} = \\ = ( \frac{2}{5} )^{ 2} + ( \frac{5}{2} )^{ 2} = \\ = \frac{4}{25} + \frac{25}{4} = \frac{16 + 625}{100} = \\ = \frac{641}{100} = 6.41$
$( - 3) ^{3} - 3.5 ^{ - 1} = - 27 - ( \frac{7}{2} )^{ - 1} = \\ = - 27 - \frac{2}{7} = - 27 \frac{2}{7}$

$- {4}^{ - 3} + ( - \frac{4}{5} ) ^{ - 2} = - \frac{1}{64} + (\frac{5}{4} ) ^{2} = \\ = - \frac{1}{64} + \frac{25}{16} = \frac{99}{64} = 1 \frac{35}{64}$
$- 3.5 ^{ - 1} + ( - 2.5) ^{ - 2} = \\ = - \frac{2}{7} + ( \frac{2}{5} )^{2} = - \frac{2}{7} + \frac{4}{25} = \\ = \frac{ - 50 + 28}{175} = - \frac{22}{175}$
$3( - 4) ^{ - 2} + 5 ^{ - 1} = \\ = \frac{3}{16} + \frac{1}{5} = \frac{15 + 16}{80} = \frac{31}{80}$
$( - 2.7) ^{0} + ( \frac{1}{7} )^{ - 1} = 1 + 7 = 8$