Найти ОДЗ функции =√ln(x^2−7x+11)/6−x

Question

Найти ОДЗ функции =√ln(x^2−7x+11)/6−x

Comments

(((

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but 2-7+11=5 why did you write like this? i really don't understand

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why didn't you write -/ln5

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OMG.I incorrectly copied the assignment.I'm an idiot sorry

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no don't use like that words please we're human and we can do some mistakes:)

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That was weird and confusing.I have corrected.Will you help me?

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what's the question

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√ln(x^2−7x+11)/6−x :D

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ok and what will I gonna do

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integral?

Answer 1

I hope this helps you

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Comments

I'm sorry but why x^2-7x+11=1?

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two cases in question in sqrt big and equal 0 and equal 1 that's rule