95 задание по алгебре

Решите задачу:

$2)64 {a}^{12} = {(4 {a}^{4}) }^{3}$
$4)36 {a}^{4} {b}^{2} = {(6 {a}^{2}b) }^{2}$
$5)0.64 {x}^{10} {y}^{4} = {(0.8 {x}^{5} {y}^{2}) }^{2}$
$7) \frac{1}{27} {a}^{2} {b}^{4} = ({ \frac{1}{3} })^{3} ( {a {b}^{2} )}^{2}$
$8) - 0.027 {x}^{6} {y}^{12} = ( { - 0.3 {x}^{2} {y}^{4} )}^{3}$

$6)121 {m}^{4} {n}^{6} = (11 {m}^{2} {n}^{3} ) ^{2}$
$3)25 {x}^{2} {y}^{2} = {(5xy)}^{2}$

$1) \:27 {a}^{6} = {(3 {a}^{2}) }^{3}$