Плиз срочно ::;:::::

Question

Плиз срочно ::;:::::

---

Answer 1

Дано

m(CuSO4 * 5H2O) = m = 1 кг

Решение

Mr(H2O) = 2Ar(H) + Ar(O) = 2 * 1 + 16 = 18

Mr(CuSO4) = Ar(Cu) + Ar(S) + 4Ar(O) = 64 + 32 + 4 * 16 = 160

Mr(CuSO4 * 5H2O) = Mr = Mr(CuSO4) + 5Mr(H2O) = 160 + 5 * 18 = 250

w(H2O) = 5Mr(H2O) / Mr = 0.36

m(H2O) = mw(H2O) = 360 г

n(H2O) = m(H2O) / M(H2O) = 360 / 18 = 20 моль

Ответ: 20 моль

Answer 2

m(CuSO4 * 5H2O) = m = 1 кг

Mr(H2O) = 2Ar(H) + Ar(O) = 2 * 1 + 16 = 18

Mr(CuSO4) = Ar(Cu) + Ar(S) + 4Ar(O) = 64 + 32 + 4 * 16 = 160

Mr(CuSO4 * 5H2O) = Mr = Mr(CuSO4) + 5Mr(H2O) = 160 + 5 * 18 = 250

w(H2O) = 5Mr(H2O) / Mr = 0.36

m(H2O) = mw(H2O) = 360 г

n(H2O) = m(H2O) / M(H2O) = 360 / 18 = 20 моль.

---

Ответ: 20 моль.