Скажите пж...!!Задание1)(3 1\6 + 5 1/7 ):349=Задание2)42,8*1/2...

Решите задачу:

$1)(3 \frac{1}{6} + 5 \frac{1}{7} ) \div 349 = ( \frac{19}{6} + \frac{36}{7} ) \div 349 = \frac{349}{42} \div 349 = \frac{349}{42} \times \frac{1}{349} = \frac{1}{42}$
$2)42.8 \times \frac{1}{2} - 2.8 \times \frac1{1}{2} = \frac{214}{5} \times \frac{1}{2} - \frac{14}{5} \times \frac{1}{2} = \frac{107 - 7}{5 } = \frac{100}{5} = 20$
$3)11.9 \div 0.34 + 2.4 \times 3.5 = 35 + 8.4 = 43.4$
$4)13576.94 \div 79 - 22.67 = 171.86 - 22.67 = 149.19$