Решите систему уравнений: 1 система (х-1) (у-1) =2 х= у+2 2 система (х-2) (у+1)=1 х-у=3 3...

Решите задачу:

$\left \{ {{(x-1)(y-1)=2} \atop {x=y+2}} \right. \left \{ {{(y+2-1)(y-1)=2} \atop {x=y+2}} \right. \left \{ {{(y+1)(y-1)=2} \atop {x=y+2}} \right. \left \{ {{y^{2}-1= 2} \atop {x=y+2}} \right. \left \{ {{y^{2}= 2+1} \atop {x=y+2}} \right. \left \{ {{y=+-\sqrt{3} } \atop {x=+-\sqrt{7} }} \right.$