8a-4(3b-(b-(1-8b))) при a+b3=2

Question

8a-4(3b-(b-(1-8b))) при a+b3=2

Answer 1

8a-4(3b-(b-(1-8b)))=8a-4(3b-(b-1+8b))=8a-4(3b-(9b-1))=8a-4(3b-9b+1)=8a-4(-6b+1)=8a+24b-4=8(a+3b)-4=8*2-4=12