1)4⁸ *25⁵ :100⁵= 2)0.8^1/7 * 5^2/7 *20^6/7=

Question

1)4⁸ *25⁵ :100⁵= 2)0.8^1/7 * 5^2/7 *20^6/7=

Answer 1

1)4^8*5^6/10^10=20^14/10^10=2^4=16
2)((4/5)^1/7)*(5^2/7)*(20^6/7)=((4^1/7)/(5^1/7))*(5^2/7)*(20^6/7)=сократить пять в степени= (4^1/7)*(5^1/7)*(20^6/7)= 20^1/7*20^6/7= 20^(1/7+6/7)=20^1= 20