Помогите решить пожалуйста.

Решите задачу:

$f(x) = 7 {x}^{3} - 2 {x}^{2} + 1 \\ f(0) = 7 \times 0 - 2 \times 0 + 1 = 1 \\ f(3) = 7 \times {3}^{3} - 2 \times {3}^{2} + 1 = 7 \times 27 - 2 \times 9 + 1 = 172 \\ f( - 2) = 7 \times ( { - 2})^{3} - 2 \times ( { - 2})^{2} + 1 = - 63 \\ f( \frac{1}{2}) = 7 \times ( { \frac{1}{2}) }^{3} - 2 \times ( { \frac{1}{2}) }^{2} + 1 = \frac{7}{8} - \frac{1}{2} + 1 = \frac{3}{8} + 1 = 1 \frac{3}{8}$