Помогите пожалуйста умоляю срочно

$1)b = 1.55 \times \frac{25}{31} + 3 \frac{29}{30} \div 0.4 = \frac{155 \times 25}{100 \times 31 } + \frac{119}{30} \div \frac{4}{10} = \frac{5 \times 1}{4 \times 1} + \frac{119 \times 10}{30 \times 4} = 1 \frac{1}{4} + \frac{119}{12} = 1 \frac{1}{4} + 9 \frac{11}{12} = 1 \frac{3}{12} + 9 \frac{11}{12} = 10 \frac{14}{12} = 10 \frac{7}{6} = 11 \frac{1}{6}$
Следовательно -в=-11 1/6
2)
$(13 \frac{1}{32} - 9 \frac{9}{16} ) \div 27.75 + 1.375 = (12 \frac{33}{32} - 9 \frac{18}{32} ) \div 27.75 + 1.375 = 3 \frac{15}{32} \div \frac{2775}{100} + 1.375 = \frac{111 \times 100}{32 \times 2775} + 1.375 = \frac{1}{8} + 1.375 = 0.125 + 1.375 = 1.5$
Следовательно в=-1.5