1.
2. x=3 \\x=0 и x=3\\b) 3-4(x+2)=5-6x \\3-4x-8-5+6x=0\\2x-10=0\\x=5\\" alt="a) x(6-2x)=0\\x=0 , 6-2x=0 => x=3 \\x=0 и x=3\\b) 3-4(x+2)=5-6x \\3-4x-8-5+6x=0\\2x-10=0\\x=5\\" align="absmiddle" class="latex-formula">
3. \frac{-11}{13} \\(\frac{-11}{13}" alt="2-8x<3+5(x+2)\\-13x<11\\x>\frac{-11}{13} \\(\frac{-11}{13}" align="absmiddle" class="latex-formula"> ; +∞)