Log(3x-6)-Log2*3=Log2*3
Решение
log₂(3x–6 ) – log₂ 3 = log₂ 3
ОДЗ: 3x - 6 > 0
3x > 6
x > 2
D(y) = (2; + ∞)
log₂(3x–6 ) = 2 log₂ 3
log₂(3x–6 ) = log₂ 3²
3x - 6 = 9
3x = 9 + 6
3x = 15
x = 5 ∈ (2; + ∞)
Ответ: x = 5