\\x^{2} -2x-8=0
\\D=(-2)^{2} -4*1*(-8)=36(6^{2} )
\\x1=\frac{-(-2)-6}{2*1} =-2
\\x2=\frac{-(-2)+6}{2*1} =4" alt="-x^{2} +2x+8=0
\\x^{2} -2x-8=0
\\D=(-2)^{2} -4*1*(-8)=36(6^{2} )
\\x1=\frac{-(-2)-6}{2*1} =-2
\\x2=\frac{-(-2)+6}{2*1} =4" align="absmiddle" class="latex-formula">
Ответ:x=-2, x=4