Найти y' Y=3x^2 x^3 Y=2/x^2 Y=1/3x^5 Y=x^5/175
Y'=(3x^2x^3)'=3*2x*3x^2=18x^3 y' =(2/x^2)'=(2x^(-2))'=2*(-2)*x^(-3)=-4/x^3 y'=1/3x^5=5/3x^4 y'=(x^5)/175=(5/175)*x^4=(x^4)/35