Решитеееееееееее по быстрееееееее

Решите задачу:

$\frac{ {4}^{6} {9}^{5} + {6}^{9}120 }{ {8}^{4} {3}^{12} - {6}^{11} } = \\ = \frac{ { ({2}^{2}) }^{6} {( {3}^{2} )}^{5} + {6}^{9}120 }{ {( {2}^{3} )}^{4} {3}^{12} - {6}^{11} } = \\ = \frac{ {2}^{12} {3}^{10} + {6}^{9} 120}{ {2}^{12} {3}^{12} - {6}^{11} } = \\ = \frac{ {2}^{9} {3}^{9} {2}^{3} 3 + {6}^{9} 120}{(2 \times 3) {}^{12} - {6}^{11} } = \\ = \frac{(2 \times 3) {}^{9} 24 + {6}^{9} 120}{ {6}^{12} - {6}^{11} } = \\ = \frac{ {6}^{9} (24 + 120)}{ {6}^{11} (6 - 1)} = \\ = \frac{144}{ {6}^{2} 5} = \frac{144}{36 \times 5} = \frac{144}{180} = 0.8$