Дано
w(C) = 85.3% = 0.853
w(H) = 14.3% = 0.143
D(H2) = 14
CxHy
Решение
Mr(CxHy) = Mr = D(H2) * Mr(H2) = 14 * 2 = 28
w(C) = xAr(C) / Mr = 12x / 28 = 0.853
12x / 28 = 0.853
12x / 28 = 0.853
12x = 24
x = 2
y = (Mr - xAr(C)) / Ar(H) = (28 - 2 * 12) / 1 = 4
C2H4
Ответ: C2H4