\\ 1 + 3t - t {}^{2} = 10 - 1.5t - t {}^{2} \\ 4.5t = 9 = > t = 2 \\ x = 1 + 3 \times 2 - 2 {}^{2} = 3" alt="x1 = x2 = > \\ 1 + 3t - t {}^{2} = 10 - 1.5t - t {}^{2} \\ 4.5t = 9 = > t = 2 \\ x = 1 + 3 \times 2 - 2 {}^{2} = 3" align="absmiddle" class="latex-formula">
Ответ: время встречи 2с; место встречи 3м