2y^2-5y+2 раскладываем через D:
D = 25-16 = 9
y1 = (5-3)/4 = 0.5
y2 = (5+3)/4 = 2
2(y-0.5)(y-2)
...=(3y - 2)(3y + 2)(2-y)y / (2(y-0.5)(y-2)(3y + 2)(1 - y)) =
y(3y-2) / (2(y-0.5)(2y-1)) = Расскладываем y(3y-2)/(2(y-1)) через D1 (y-0.5) (2y-1):
2y^2 +2y +0.5
D1 = 0
y= -2/2 = -1
(y+1)