помогите решить уравнения: 1)5,04:(104,2-x)=1,2 2)1,2x+4,5x-0,7=1,01

1) $5,04:(104,2-x)=1,2$

$104,2-x=5,04:1,2$

$104,2-x=4,2$

$x=100$

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$5,04:(104,2-100)=1,2$ (это проверка)

$5,04:4,2=1,2$

$1,2=1,2$

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2) $1,2x+4,5x-0,7=1,01$

$5,7x-0,7=1,01$

$5,7x=1,01+0,7$

$5,7x=1,71$

$x=1,71:5,7$

$x=0,3$

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$1,2\cdot0,3+4,5\cdot0,3-0,7=1,01$

$0,36+1,35-0,7=1,01$

$1,01=1,01$