ПОМОГИТЕ пожалуйста

Решите задачу:

$1) \alpha - \beta = 30° \\ \alpha + \beta = 180° \\ 2 \alpha = 210° \\ \alpha = 105° \\ \beta = 180° - 105° = 75° \\ otvet \\ \alpha = 105° \\ \beta = 75°$
$2) < 1 = <4 \\ dokazat < 2 = < 3 \\ < 1 = 180° - < 2 \\ < 4 = 180° - < 3 \\ < 1 = < 4(po \: usl.) \\ polychaem \\ 180° - < 2 = 180° - < 3 \\ < 2 = < 3 \\ dokazali.$
$3) \alpha \div \beta = 1 \div 5 \\ 1 + 5 = 6 \\ 180° \div 6 = 30° - na \: odny \: chast \\ \alpha = 1 \times 30° = 30°\\ \beta = 5 \times 30° = 150° \\$