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Решите задачу:

$18 \frac{61}{92} - 4 \frac{13}{46} + 12 \frac{9}{23} = \\ = (18 - 4 + 12) + \\ + ( \frac{61}{92} - \frac{26}{92} + \frac{36}{92} ) = \\ = 26 \frac{71}{92} \\$
$\frac{10}{21} \div \frac{5}{6} - \frac{2}{9} \times \frac{3}{4} = \\ = \frac{10 \times 6}{21 \times 5} - \frac{2 \times 3}{9 \times 4} = \\ = \frac{2 \times 2}{7 \times 1} - \frac{1 \times 1}{3 \times 2} = \frac{4}{7} - \frac{1}{6} = \\ = \frac{24 - 7}{42} = \frac{17}{42}$
$(2 - \frac{7}{10} ) \div ( \frac{5}{7} + \frac{3}{14} ) = \\ = \frac{20 - 7}{10} \div \frac{2 \times 5 + 3}{14} = \\ = \frac{13}{10} \times \frac{14}{13} = \frac{7}{5} = 1 \frac{2}{5}$