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$\frac{(4x)^{11}*(16x)^{2}*4}{(4x^2)^3*(64x)^4}=-108\\\\\frac{4^{11}x^{11}*(4^2)^2x^{2}*4}{4^3x^6*(4^3)^4x^4}=-108\\\\\frac{4^{11}x^{11}*4^4x^{2}*4}{4^3x^6*4^{12}x^4}=-108\\\\\frac{4^{11+4+1}x^{11+2}}{4^{3+12}x^{6+4}}=-108\\\\\frac{4^{16}x^{13}}{4^{15}x^{10}}=-108\\\\4^{16-15}x^{13-10}=-108\\\\4x^3=-108\\\\x^3=-\frac{108}{4}\\\\x^3=-27\\\\x=\sqrt[3]{-27}\\\\x=-3$

Ответ: х = - 3