1) ![(x-3)^{\frac{1}{4} } =\sqrt[4]{x-3} \\ \\ x-3\geq 0\\ \\ x\geq 3](https://tex.z-dn.net/?f=%28x-3%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%20%3D%5Csqrt%5B4%5D%7Bx-3%7D%20%5C%5C%20%5C%5C%20x-3%5Cgeq%200%5C%5C%20%5C%5C%20x%5Cgeq%203 "(x-3)^{\frac{1}{4} } =\sqrt[4]{x-3} \\ \\ x-3\geq 0\\ \\ x\geq 3")
x ∈ [3; +∞)
2) ![(y+3)^{}\frac{2}{5} =\sqrt[5]{(y+3)^{2}}](https://tex.z-dn.net/?f=%28y%2B3%29%5E%7B%7D%5Cfrac%7B2%7D%7B5%7D%20%3D%5Csqrt%5B5%5D%7B%28y%2B3%29%5E%7B2%7D%7D "(y+3)^{}\frac{2}{5} =\sqrt[5]{(y+3)^{2}}")
т.к. квадрат любого числа есть число неотрицательное, то y ∈ (-∞; +∞)
3) 
0\\ \\ -2y>-4\\ \\ y<2" alt="(4-2y)^{-\frac{1}{6}} =\frac{1}{\sqrt[6]{4-2y}} \\ \\ 4-2y>0\\ \\ -2y>-4\\ \\ y<2" align="absmiddle" class="latex-formula">
y ∈ (-∞; +2)