1) 6\(x+1)(x+2)+8\(x-1)(x+4)=1 2) x\x-3+4\x+3=18\x^2-9 3)15- (2x-4-3x\5)=7x- x-7\2-5x...

Question

1) 6\(x+1)(x+2)+8\(x-1)(x+4)=1 2) x\x-3+4\x+3=18\x^2-9 3)15- (2x-4-3x\5)=7x- x-7\2-5x 4)x^6-19x^3-216=0 5)x^4-y^4\4x^2-2x+y-y^2:x^3-x^2y+xy^2-y^3\2x-y

Answer 1

V-это корень
1)(x+1)*(x+2) = x^2 +3x+2;
(x-1)*(x+4) = x^2+3x - 4;
x^2 + 3x = y;
(6/(y+2)) + (8/(y-4)) = 1;
y не=-2 и y не=4;
6*(y-4) + 8*(y+2) = (y+2)*(y-4);
6y-24 + 8y +16 = y^2 - 2y -8;
y^2 -y*(2+8+6) - 8 + 24 -16 = 0;
y^2 - 16y =0;
y*(y-16) = 0;
y=0 или y-16=0;
1) y=0; <=> x^2+3x = 0; <=> x*(x+3) = 0; <=> x1=0; или x2=-3.
2) y-16 = 0; <=> x^2+3x - 16 = 0;
D = 3^2 + 4*16 = 9+64 = 73;
x3 = (-3+(V73))/2;
x4 = (-3-(V73))/2.
2)на фото
ну наверное так

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